Solve the system of equations.
x – 2y = 2
3x + y = 6
| Equation 1: x – 2y = 2 –2y
=
–x + 2 ![]() =
+ ![]() y
=
x – 1slope = and y-intercept = –1 |
Equation 2: 3x + y = 6 y
=
–3x + 6
slope = – and y-intercept = 6 |
Now that you know the slope and y-intercept of each equation, graph both lines on a coordinate plane and find the point of intersection. Recall that you will plot the y-intercept first, and then use the slope to find a second point.

You can see that the point of intersection is the ordered pair (2, 0). The final step of this process is to check your solution in both equations. Substitute 2 for x and 0 for y.
Equation 1:
x – 2y
=
2
2 – 2(0)
![]() 2
2 – 0
![]() 2
2
=
2
![]() |
Equation 2: 3x + y
=
6
3(2) + 0
![]() 6
6 + 0
![]() 6
6
=
6
![]() |

Finally, review solving systems of equations using the elimination method. Remember, this is just another way of getting to the same solution.